(5a-20/4a^2)=(1/4a)+(1/2a)

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Solution for (5a-20/4a^2)=(1/4a)+(1/2a) equation: 


a in (-oo:+oo)

5*a-((20/4)*a^2) = (1/4)*a+(1/2)*a // - (1/4)*a+(1/2)*a

5*a-((20/4)*a^2)-((1/4)*a)-((1/2)*a) = 0

5*a-5*a^2+(-1/4)*a+(-1/2)*a = 0

17/4*a-5*a^2 = 0

DELTA = (17/4)^2-(-5*0*4)

DELTA = 289/16

DELTA > 0

a = ((289/16)^(1/2)-17/4)/(-5*2) or a = (-(289/16)^(1/2)-17/4)/(-5*2)

a = 0 or a = 17/20

a in { 0, 17/20 }

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